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A092142 Compute the continued fraction expansion of Pi; multiply each term by i, the square root of -1, compute this new continued fraction and get a number with a real part equal to 0. Then compute the regular continued fraction of the imaginary part of that new number. 0
2, 1, 5, 1, 12, 1, 301, 2, 78, 1, 14, 1, 1, 1, 10, 1, 1, 2, 4, 1, 4, 1, 94, 1, 3, 1, 1, 1, 8, 1, 5, 1, 2, 2, 4, 1, 10, 1, 8, 1, 10, 1, 13, 1, 158, 1, 42, 1, 18, 1, 21, 1, 8, 2, 2, 1, 3, 1, 2, 3, 23, 1, 8, 2, 39, 1, 3, 1, 1, 1, 7, 2, 2, 1, 7, 1, 5, 3, 53, 1, 14, 1, 6, 1, 15, 1, 14, 2, 5, 1, 28, 1, 1, 2, 4 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,1

LINKS

Table of n, a(n) for n=0..94.

PROG

(PARI) k=contfracpnqn(contfrac(Pi, 500)*I); contfrac(imag(k[1, 1]/k[2, 1]), 200)

CROSSREFS

Sequence in context: A054251 A163963 A119763 * A299161 A327249 A173108

Adjacent sequences:  A092139 A092140 A092141 * A092143 A092144 A092145

KEYWORD

easy,nonn

AUTHOR

Thomas Baruchel, Mar 31 2004

STATUS

approved

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Last modified October 22 09:56 EDT 2019. Contains 328315 sequences. (Running on oeis4.)