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A090203
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a(n) = p-th digit of phi where p = n-th prime.
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1
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6, 1, 0, 3, 7, 9, 8, 8, 5, 3, 5, 7, 3, 9, 8, 8, 4, 8, 5, 4, 2, 2, 7, 2, 1, 4, 4, 0, 8, 3, 3, 2, 9, 1, 7, 6, 4, 9, 5, 5, 6, 8, 9, 8, 2, 7, 6, 6, 0, 2, 0, 2, 9, 3, 4, 7, 2, 0, 5, 9, 4, 1, 9, 0, 4, 7, 5, 8, 4, 2, 5, 0, 1, 0, 8, 4, 2, 7, 8, 6, 0, 9, 2, 0, 1, 1, 0, 1, 1, 7, 6, 8, 5, 6, 7, 3, 3, 8, 3, 9, 7, 7, 1, 2, 0
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OFFSET
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2,1
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COMMENTS
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The prime-th digits of Phi.
Is the number 6.10379885357398... irrational, transcendental?
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LINKS
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EXAMPLE
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The 5th prime is 11. The 11th digit of Phi is 7, the 5th term in the sequence.
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MATHEMATICA
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With[{nn=600}, Pick[RealDigits[GoldenRatio, 10, nn][[1]], If[PrimeQ[#], 1, 0]&/@Range[nn], 1]] (* Harvey P. Dale, Apr 22 2012 *)
Module[{nn=110, gr}, gr=RealDigits[GoldenRatio, 10, Prime[nn]][[1]]; Table[gr[[p]], {p, Prime[ Range[nn]]}]] (* Harvey P. Dale, Dec 07 2022 *)
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PROG
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(PARI) \primeth.gp primeth(n) = { default(realprecision, 1000); p=Str((sqrt(5)+1)/2*10^999); default(realprecision, 28); forprime(x=2, n, print1(mid(p, x, 1)", ") ) } mid(str, s, n) = { v =""; tmp = Vec(str); ln=length(tmp); for(x=s, s+n-1, v=concat(v, tmp[x]); ); return(v) }
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CROSSREFS
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KEYWORD
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base,easy,nonn
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AUTHOR
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STATUS
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approved
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