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A089242
Sequence is S(infinity), where S(1) = 1, S(m+1) = concatenation S(m), a(m)+1, S(m) and a(m) is the m-th term of S(m). a(m) is also the m-th term of the sequence.
2
1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 3, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 4, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1, 2, 1, 3, 1, 2, 1, 2, 1
OFFSET
1,2
COMMENTS
S(m) has 2^m - 1 elements and is palindromic for all m.
First occurrence of k: 1,2,4,16,65536,...,. A014221: a(n+1) = 2^a(n). This is an Ackermann function. - Robert G. Wilson v, May 30 2006
LINKS
FORMULA
a(m) = number of c's such that 0 = c(c(c(c(...c(m)...)))), where 2^c(n) is the highest power of 2 which divides evenly into n (i.e., a(m) = 1 + a(c(m))); also c(m) = A007814(m).
In other words, a(n) = number of iterates of A007814 until a zero is encountered.
Multiplicative with a(2^e) = 1 + a(e), a(p^e) = 1 for odd prime p. - Andrew Howroyd, Jul 27 2018
Asymptotic mean: Limit_{m->oo} (1/m) * Sum_{k=1..m} a(k) = Sum_{k>=1} a(2^(k-1))/2^k = 1.6980544744753405... . - Amiram Eldar, Oct 29 2022
MATHEMATICA
c[n_] := (i++; Block[{k = 0, m = n}, While[ EvenQ[m], k++; m /= 2]; k]); f[n_] := (i = 0; NestWhile[c, n, # >= 1 &]; i); Array[f, 105] (* Robert G. Wilson v, May 30 2006 *)
CROSSREFS
Sequence in context: A327533 A327518 A174532 * A349258 A349326 A185894
KEYWORD
nonn,easy,mult
AUTHOR
Leroy Quet, Dec 13 2003
EXTENSIONS
More terms from David Wasserman, Aug 31 2005
STATUS
approved