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A087552
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a(1) = 1, then the smallest prime divisor of A065447(n) not included earlier.
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0
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1, 2, 11, 5, 3, 29, 101, 113, 41, 271, 7, 13, 239, 613, 73, 137, 37, 8291, 9091, 157637, 313, 21649, 9901, 2733970560857, 53, 79, 229, 4649, 31, 13001, 17, 19, 6529, 664193, 6781, 52579, 1111111111111111111
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OFFSET
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1,2
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COMMENTS
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Conjecture: Every prime is a member and this is a rearrangement of the noncomposite numbers.
Proof of conjecture: primes 2=a(1) and 5=a(3) are terms, while any other prime divides infinitely many numbers of the form A002275([(n+1)/2]) = (10^[(n+1)/2]-1)/9, which in turn divide A065447(n). Thus every prime will sooner or later appear as a(n). - Max Alekseyev, Jul 03 2019
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LINKS
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EXAMPLE
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a(6) = 29; smallest prime divisor of 100111000011111000000 not included earlier is 29. The prime divisors are 2, 3, 5, 29, 37, 97 and 106872959.
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CROSSREFS
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KEYWORD
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base,more,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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