1,3

The number N(x) of Niven numbers less than x is given by N(x) = (c+o(1))*x/log(x).

Table of n, a(n) for n=1..105.

Jean-Marie De Koninck and Nicolas Doyon, Large and Small Gaps Between Consecutive Niven Numbers, J. Integer Seqs., Vol. 6, 2003, Article 03.2.5.

c = (14/27)*log(10).

1.1939330111820977620834029765030036632005711422519563579432....

(PARI) (14/27)*log(10) \\ Michel Marcus, Jan 15 2018

Cf. A005349.

Sequence in context: A159467 A198608 A273637 * A199866 A276558 A196829

Adjacent sequences: A086702 A086703 A086704 * A086706 A086707 A086708

cons,nonn

Benoit Cloitre, Jul 28 2003

approved