OFFSET
0,2
FORMULA
a(n)=A074854(2^n)=; a(n)=floor(c*2^(2^n)) where c=sum(k>=0, 1/2^(2^k))=0.81642150902...
a(n + 1) = 1 + a(n)*2^(2^n), a(0) = 1 [From Peter Moxey (pmoxey(AT)live.com), Mar 14 2010]
CROSSREFS
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Jun 19 2003
STATUS
approved