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A084776
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a(n) = sum of absolute-valued coefficients of (1+2*x-x^2)^n.
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8
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1, 4, 12, 36, 100, 300, 776, 2412, 6304, 19036, 50952, 148896, 393452, 1211444, 3167004, 9672772, 25295248, 76084796, 200590424, 608621376, 1617201648, 4908511140, 12658776540, 38907904188, 102775961200, 310485090044
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OFFSET
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0,2
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LINKS
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FORMULA
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a(n) = Sum_{k=0..2*n} abs(f(n, k)), where f(n, k) = (sqrt(2) - 1)^k * Sum_{j=0..k} binomial(n, j)*binomial(n, k-j)*(-1)^j*(1+sqrt(2))^(2*j). - G. C. Greubel, Jun 03 2023
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MATHEMATICA
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T[n_, k_]:=T[n, k]=SeriesCoefficient[Series[(1+2*x-x^2)^n, {x, 0, 2n}], k];
a[n_]:= a[n]= Sum[Abs[T[n, k]], {k, 0, 2n}];
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PROG
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(PARI) for(n=0, 40, S=sum(k=0, 2*n, abs(polcoeff((1+2*x-x^2)^n, k, x))); print1(S", "))
(Magma)
m:=40;
R<x>:=PowerSeriesRing(Integers(), 2*(m+2));
f:= func< n, k | Coefficient(R!( (1+2*x-x^2)^n ), k) >;
[(&+[ Abs(f(n, k)): k in [0..2*n]]): n in [0..m]]; // G. C. Greubel, Jun 03 2023
(SageMath)
def f(n, k):
P.<x> = PowerSeriesRing(QQ)
return P( (1+2*x-x^2)^n ).list()[k]
def a(n): return sum( abs(f(n, k)) for k in range(2*n+1) )
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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