OFFSET
1,3
COMMENTS
There are exactly 18 numbers such that 2^n uses only distinct digits.
a(n) can have at most 10 digits. As 2^34 has 11 digits, a(n) < 34. - David A. Corneth, Aug 03 2015
Subsequence of A052060. - R. J. Mathar, Sep 17 2008
FORMULA
a(n) = log_2(A260814(n)). - Zak Seidov, Aug 02 2015
EXAMPLE
29 is the last term with 2^29 = 536870912 = A260814(18). - Zak Seidov, Aug 02 2015
MATHEMATICA
Select[Range[0, 34], Max@ DigitCount[2^#] == 1 &] (* Michael De Vlieger, Aug 03 2015 *) (* with corrections by Zak Seidov, Aug 05 2015 *)
PROG
(PARI) lista() = {lim = ceil(log(10^11)/(log(2))); for (n=0, lim, d = digits(2^n); if (#vecsort(d, , 8) == #d, print1(n, ", ")); ); } \\ Michel Marcus, Aug 03 2015
CROSSREFS
KEYWORD
fini,nonn,full,base
AUTHOR
Zak Seidov, Jul 01 2003
STATUS
approved
