1,3
There are exactly 9 such n's that 3^n uses only distinct digits (in base 10).
Table of n, a(n) for n=1..9.
9 is (the last!) term because 3^9=19683 uses only distinct digits.
Select[Range[0, 10], Max[DigitCount[3^#]]<2&] (* Harvey P. Dale, Jan 24 2021 *)
Sequence in context: A243369 A228052 A308072 * A021085 A031006 A031978
Adjacent sequences: A084686 A084687 A084688 * A084690 A084691 A084692
fini,nonn,full,base
Zak Seidov, Jul 01 2003
approved
