A083396 Least n such that n and 2k+n are both brilliant numbers.

4, 6, 4, 6, 4, 9, 21, 9, 169, 15, 121, 25, 9, 21, 289, 221, 15, 253, 209, 9, 247, 143, 253, 121, 341, 169, 323, 437, 319, 187, 299, 649, 121, 221, 253, 49, 377, 247, 143, 209, 391, 169, 35, 121, 209, 299, 49, 25, 221, 21, 187, 143, 15, 35, 143, 9, 209, 377, 25, 49, 21

Offset

1,1

Comments

Conjecture: for any k >= 1 there will always be a brilliant constellation of the form {n, 2k+n} for some n. (True for all k <= 5000.)

Links

Table of n, a(n) for n=1..61.

Example

a(9)=169 because 169=13*13 and 169+18=11*17.

Crossrefs

Cf. A078972, A083284, A083285.

Sequence in context: A168428 A351126 A127018 * A142973 A181110 A199959

Adjacent sequences: A083393 A083394 A083395 * A083397 A083398 A083399

Keyword

base,nonn

Author

Jason Earls, Jun 06 2003

Status

approved