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Least n such that n and 2k+n are both brilliant numbers.
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%I #5 Dec 15 2017 17:36:19

%S 4,6,4,6,4,9,21,9,169,15,121,25,9,21,289,221,15,253,209,9,247,143,253,

%T 121,341,169,323,437,319,187,299,649,121,221,253,49,377,247,143,209,

%U 391,169,35,121,209,299,49,25,221,21,187,143,15,35,143,9,209,377,25,49,21

%N Least n such that n and 2k+n are both brilliant numbers.

%C Conjecture: for any k >= 1 there will always be a brilliant constellation of the form {n, 2k+n} for some n. (True for all k <= 5000.)

%e a(9)=169 because 169=13*13 and 169+18=11*17.

%Y Cf. A078972, A083284, A083285.

%K base,nonn

%O 1,1

%A _Jason Earls_, Jun 06 2003