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A081570
Fifth binomial transform of F(n+1).
7
1, 6, 37, 233, 1490, 9633, 62753, 410926, 2700349, 17786985, 117346714, 774991289, 5121849473, 33865596822, 223987930325, 1481764925737, 9803764203682, 64870223394129, 429263295428641, 2840659771285310, 18798621916707821
OFFSET
0,2
COMMENTS
Binomial transform of A081569.
Case k=5 of family of recurrences a(n) = (2k+1)*a(n-1) - A028387(k-1)*a(n-2), a(0)=1, a(1)=k+1.
FORMULA
a(n) = 11*a(n-1) - 29*a(n-2), a(0)=1, a(1)=6.
a(n) = (1/2 - sqrt(5)/10)*(11/2 - sqrt(5)/2)^n + (sqrt(5)/10 + 1/2)*(sqrt(5)/2 + 11/2)^n .
G.f.: (1-5*x)/(1-11*x+29*x^2).
a(n) = Sum_{k=0..n} A094441(n,k)*5^k. - Philippe Deléham, Dec 14 2009
MAPLE
seq(coeff(series((1-5*x)/(1-11*x+29*x^2), x, n+1), x, n), n = 0 .. 30); # G. C. Greubel, Aug 12 2019
MATHEMATICA
CoefficientList[Series[(1-5x)/(1 -11x +29x^2), {x, 0, 30}], x] (* Vincenzo Librandi, Aug 09 2013 *)
LinearRecurrence[{11, -29}, {1, 6}, 30] (* Harvey P. Dale, Aug 04 2022 *)
PROG
(Magma) I:=[1, 6]; [n le 2 select I[n] else 11*Self(n-1)-29*Self(n-2): n in [1..30]]; // Vincenzo Librandi, Aug 09 2013
(PARI) my(x='x+O('x^30)); Vec((1-5*x)/(1-11*x+29*x^2)) \\ G. C. Greubel, Aug 12 2019
(SageMath)
def A081570_list(prec):
P.<x> = PowerSeriesRing(ZZ, prec)
return P((1-5*x)/(1-11*x+29*x^2)).list()
A081570_list(30) # G. C. Greubel, Aug 12 2019
(GAP) a:=[1, 6];; for n in [3..30] do a[n]:=11*a[n-1]-29*a[n-2]; od; a; # G. C. Greubel, Aug 12 2019
CROSSREFS
Cf. A000045.
Sequence in context: A390591 A161734 A387007 * A122898 A317629 A081912
KEYWORD
easy,nonn
AUTHOR
Paul Barry, Mar 22 2003
STATUS
approved