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A081555
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a(n) = 6*a(n-1) - a(n-2) - 4, a(0)=3, a(1)=7.
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3
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3, 7, 35, 199, 1155, 6727, 39203, 228487, 1331715, 7761799, 45239075, 263672647, 1536796803, 8957108167, 52205852195, 304278004999, 1773462177795, 10336495061767, 60245508192803, 351136554095047, 2046573816377475, 11928306344169799, 69523264248641315
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OFFSET
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0,1
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COMMENTS
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2*(a(2*n+1) + 1) is a perfect square.
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LINKS
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FORMULA
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a(n) = (3 + 2*sqrt(2))^n + (3 - 2*sqrt(2))^n + 1.
G.f.: (3-14*x+7*x^2)/((1-x)*(1-6*x+x^2)).
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MAPLE
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seq(coeff(series((3-14*x+7*x^2)/((1-x)*(1-6*x+x^2)), x, n+1), x, n), n = 0 ..30); # G. C. Greubel, Aug 13 2019
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MATHEMATICA
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a[n_]:= a[n] = 6*a[n-1] -a[n-2] -4; a[0] = 3; a[1] = 7; Table[a[n], {n, 0, 25}]
LinearRecurrence[{7, -7, 1}, {3, 7, 35}, 30] (* G. C. Greubel, Aug 13 2019 *)
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PROG
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(PARI) a(n)=1+2*real((3+quadgen(32))^n)
(PARI) a(n)=1+2*subst(poltchebi(abs(n)), x, 3)
(PARI) a(n)=if(n<0, a(-n), 1+polsym(1-6*x+x^2, n)[n+1])
(Magma) R<x>:=PowerSeriesRing(Integers(), 30); Coefficients(R!( (3-14*x+7*x^2)/((1-x)*(1-6*x+x^2)) )); // G. C. Greubel, Aug 13 2019
(Sage)
P.<x> = PowerSeriesRing(ZZ, prec)
return P((3-14*x+7*x^2)/((1-x)*(1-6*x+x^2))).list()
(GAP) a:=[3, 7];; for n in [3..30] do a[n]:=6*a[n-1]-a[n-2]-4; od; a; # G. C. Greubel, Aug 13 2019
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CROSSREFS
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KEYWORD
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easy,nonn
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AUTHOR
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Mario Catalani (mario.catalani(AT)unito.it), Mar 24 2003
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STATUS
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approved
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