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 A080345 a(n) is the number of prime factors in Fibonacci(prime(n)); that is, in the Fibonacci number whose index is the n-th prime. 4
 0, 1, 1, 1, 1, 1, 1, 2, 1, 1, 2, 3, 2, 1, 1, 2, 2, 2, 3, 2, 2, 2, 1, 2, 4, 2, 3, 2, 2, 2, 2, 1, 1, 3, 4, 2, 4, 4, 2, 2, 3, 3, 2, 2, 4, 2, 4, 4, 2, 5, 3, 4, 3, 2, 3, 3, 4, 2, 2, 3, 4, 2, 4, 4, 4, 3, 2, 3, 5, 4, 2, 1, 7, 5, 4, 3, 3, 2, 2, 4, 3, 4, 1, 1, 5, 5, 1, 3, 5, 3, 2, 3, 4, 3, 4, 6, 1, 3, 4, 3 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,8 COMMENTS In all known examples, Fibonacci(prime(n)) is squarefree, in which case a(n) is well-defined, i.e., the number of distinct prime factors equals the total number of prime factors. But if for some n, Fibonacci(prime(n)) has a repeated prime factor, then a(n) is not well-defined. - Jonathan Sondow, Oct 22 2015 LINKS Amiram Eldar, Table of n, a(n) for n = 1..222 (terms 1..168 from T. D. Noe) Blair Kelly, Fibonacci and Lucas Factorizations FORMULA a(n) = A001221(A000045(A000040(n))). - Michel Marcus, Oct 22 2015 EXAMPLE a(12) = 3 because the 12th prime is 37 and Fibonacci(37) = 24157817 = 73 * 149 * 2221 has 3 prime factors. - clarified by Jonathan Sondow, Oct 21 2015 MATHEMATICA Table[Length[FactorInteger[Fibonacci[Prime[n]]]], {n, 60}] PrimeNu[Fibonacci[Prime[Range[100]]]] (* Harvey P. Dale, Mar 13 2016 *) PROG (PARI) a(n) = omega(fibonacci(prime(n))); \\ Michel Marcus, Oct 22 2015 CROSSREFS Cf. A001605, A014600, A022307. Sequence in context: A204030 A234503 A236325 * A285202 A004737 A255616 Adjacent sequences:  A080342 A080343 A080344 * A080346 A080347 A080348 KEYWORD hard,nonn AUTHOR T. D. Noe, Feb 16 2003 STATUS approved

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Last modified December 5 20:45 EST 2019. Contains 329779 sequences. (Running on oeis4.)