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A079878
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a(1)=1, then a(n)=2*a(n-1) if 2*a(n-1)<=n, a(n)=2*a(n-1)-n otherwise.
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5
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1, 2, 1, 2, 4, 2, 4, 8, 7, 4, 8, 4, 8, 2, 4, 8, 16, 14, 9, 18, 15, 8, 16, 8, 16, 6, 12, 24, 19, 8, 16, 32, 31, 28, 21, 6, 12, 24, 9, 18, 36, 30, 17, 34, 23, 46, 45, 42, 35, 20, 40, 28, 3, 6, 12, 24, 48, 38, 17, 34, 7, 14, 28, 56, 47, 28, 56, 44, 19, 38, 5, 10, 20, 40, 5, 10, 20, 40, 1, 2
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OFFSET
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1,2
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COMMENTS
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LINKS
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FORMULA
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It seems that sum(k=1, n, a(k))/n^2 ->1/4
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MATHEMATICA
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nxt[{n_, a_}]:={n+1, If[2a<=n+1, 2a, 2a-n-1]}; Transpose[NestList[nxt, {1, 1}, 80]][[2]] (* Harvey P. Dale, Jul 20 2015 *)
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PROG
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(PARI) a=1; for(n=2, 100, b=if(sign(2*a-n)-1, 2*a, 2*a-n); a=b; print1(b, ", "))
(Haskell)
a079878 n = a079878_list !! (n-1)
a079878_list = 1 : zipWith (\x n -> if x <= n then x else x - n)
(map (* 2) a079878_list) [2..]
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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