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A077070 Triangle read by rows: T(n,k) is the power of 2 in denominator of coefficients of Legendre polynomials, where n >= 0 and 0 <= k <= n. 4
0, 1, 1, 3, 2, 3, 4, 4, 4, 4, 7, 5, 6, 5, 7, 8, 8, 7, 7, 8, 8, 10, 9, 10, 8, 10, 9, 10, 11, 11, 11, 11, 11, 11, 11, 11, 15, 12, 13, 12, 14, 12, 13, 12, 15, 16, 16, 14, 14, 15, 15, 14, 14, 16, 16, 18, 17, 18, 15, 17, 16, 17, 15, 18, 17, 18, 19, 19, 19, 19, 18, 18, 18, 18, 19, 19, 19, 19, 22, 20, 21, 20, 22, 19, 20, 19, 22, 20, 21, 20, 22 (list; table; graph; refs; listen; history; text; internal format)
OFFSET
0,4
LINKS
FORMULA
T(n, k) = A007814(A144816(n, k)). - Michel Marcus, Jan 29 2022
T(n, k) = 2*n - wt(n-k) - wt(k) where wt = A000120 is the binary weight. - Kevin Ryde, Jan 29 2022
EXAMPLE
Triangle T(n,k) (with rows n >= 0 and columns k >= 0) begins as follows:
0;
1, 1;
3, 2, 3;
4, 4, 4, 4;
7, 5, 6, 5, 7;
8, 8, 7, 7, 8, 8;
10, 9, 10, 8, 10, 9, 10;
...
MAPLE
T:= n-> (p-> seq(padic[ordp](denom(coeff(p, x, i)), 2)
, i=0..2*n, 2))(orthopoly[P](2*n, x)):
seq(T(n), n=0..12); # Alois P. Heinz, Jan 25 2022
MATHEMATICA
T[n_, k_] := IntegerExponent[Denominator[Coefficient[LegendreP[2n, x], x, 2k]], 2]; Table[T[n, k], {n, 0, 11}, {k, 0, n}] // Flatten (* Jean-François Alcover, Apr 28 2017 *)
PROG
(PARI) {T(n, k) = if( k<0 || k>n, 0, -valuation( polcoeff( pollegendre(2*n), 2*k), 2))}
(PARI) T(n, k) = 2*n - hammingweight(n-k) - hammingweight(k); \\ Kevin Ryde, Jan 29 2022
CROSSREFS
Cf. A005187 (column k=0), A101925 (column k=1), A077071 (row sums), A144816 (denominators).
Sequence in context: A272886 A098822 A131597 * A374560 A075988 A029150
KEYWORD
nonn,tabl
AUTHOR
Michael Somos, Oct 25 2002
STATUS
approved

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Last modified September 18 03:51 EDT 2024. Contains 375995 sequences. (Running on oeis4.)