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A076109
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Least positive k such that k^n is the sum of n consecutive integers, or 0 if no such k exists.
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4
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1, 1, 3, 0, 5, 3, 7, 0, 3, 5, 11, 0, 13, 7, 15, 0, 17, 3, 19, 0, 21, 11, 23, 0, 5, 13, 3, 0, 29, 15, 31, 0, 33, 17, 35, 0, 37, 19, 39, 0, 41, 21, 43, 0, 15, 23, 47, 0, 7, 5, 51, 0, 53, 3, 55, 0, 57, 29, 59, 0, 61, 31, 21, 0, 65, 33, 67, 0, 69, 35, 71, 0, 73, 37, 15, 0, 77, 39, 79, 0
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OFFSET
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1,3
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COMMENTS
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No k exists precisely when n == 0 (mod 4).
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LINKS
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FORMULA
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a(n) = (n*A076107(n)+(n^2-n)/2)^(1/n) for n != 0 (mod 4).
a(p) = p if p is a prime.
Multiplicative with a(2^1) = 1; a(2^e) = 0 if e >= 2; a(p^e) = p if p >= 3. - David W. Wilson, Jun 10 2005
a(4k) = 0; otherwise a(n) = p1*...*pm where p1, ..., pm are all distinct odd primes dividing n. - Max Alekseyev, Jun 10 2005
Sum_{k=1..n} a(k) ~ c * n^2, where c = (3/8) * Product_{p prime} (1 - 1/(p*(p+1))) = (3/8) * A065463 = 0.264165... . - Amiram Eldar, Oct 28 2022
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MATHEMATICA
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f[p_, e_] := If[p == 2, Boole[e == 1], p]; a[n_] := Times @@ f @@@ FactorInteger[n]; Array[a, 100] (* Amiram Eldar, Sep 09 2020 *)
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PROG
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(PARI) for(n=1, 100, t=n*(n-1)/2:f=0:for(r=1, 10^4, if((r^n-t)%n==0, f=r:break)):print1(f", "))
(PARI) { A076109(n) = if(n%4==0, return(0)); if(n%2==0, n\=2); vecprod(factorint(n)[, 1]); } \\ Max Alekseyev, Jun 10 2005
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CROSSREFS
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KEYWORD
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nonn,easy,mult
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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