OFFSET
1,1
COMMENTS
This s(n) := Sum_{j=0..n-1} 1/(4*j + 3), for n >= 1, equals (Psi(n + 3/4) - Psi(3/4))/4, with the digamma function Psi(z). See Abramowitz-Stegun, p. 258, eqs. 6.3.7 and 6.3.5, with z -> 3/4. A200134 = -Psi(3/4). - Wolfdieter Lang, Apr 06 2022
LINKS
Abramowitz and I. A. Stegun, eds., Handbook of Mathematical Functions. p.258, National Bureau of Standards, Applied Math. Series 55, Tenth Printing, 1972 [alternative scanned copy]. p. 258.
FORMULA
Denominator( (Psi(n + 3/4) - Psi(3/4))/4 ). See the comment above. - Wolfdieter Lang, Apr 05 2022
MATHEMATICA
Table[ Denominator[ Sum[1/i, {i, 3/4, n}]], {n, 1, 20}]
PROG
(Python)
from fractions import Fraction
def a(n): return sum(Fraction(1, 4*i-1) for i in range(1, n+1)).denominator
print([a(n) for n in range(1, 21)]) # Michael S. Branicky, Mar 21 2021
(PARI) a(n) = denominator(sum(i=1, n, 1/(4*i-1))); \\ Michel Marcus, Mar 21 2021
CROSSREFS
KEYWORD
easy,frac,nonn
AUTHOR
Robert G. Wilson v, Aug 27 2002
STATUS
approved