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A074487
a(1)=1, then "jump over next square": a(n) = 2*(a(n-1)+1)^2-a(n-1).
1
1, 7, 121, 29647, 1757978161, 6180974434379818327, 76408889916913830205838054898189612841, 11676636916670111980512852400247542904848802859324947344926081051625513021087
OFFSET
1,2
COMMENTS
The rule "jump over next something" can be varied, see A075694, A075695.
FORMULA
a(1)=1, a(n) = 2*(a(n-1)+1)^2 - a(n-1).
EXAMPLE
a(1)=1; next square is (a(1)+1)^2=4; "jump over" it: 4+(4-1)=7; a(2)=7; next square is (a(2)+1)^2=64; "jump over" it: 64+(64-7)=121.
MAPLE
a(1) := 1; a(n) := 2*(a(n-1)+1)^2-a(n-1);
CROSSREFS
Sequence in context: A211103 A012103 A012086 * A192566 A322090 A360337
KEYWORD
easy,nonn
AUTHOR
Zak Seidov, Sep 26 2002
STATUS
approved