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A074488 a(1)=1, then "jump over next cube": a(n) = 2*(a(n-1)+1)^3-a(n-1). 0
1, 15, 8177, 1093884103327, 2617845000308809034415180474721383777, 35880772304755070470965980424546414275930627947903988794595699467727630030276033995103117884255220637999070127 (list; graph; refs; listen; history; text; internal format)
OFFSET
1,2
COMMENTS
The rule "jump over next something" can be varied, see A075694, A075695.
LINKS
FORMULA
a(1)=1, a(n) = 2*(a(n-1)+1)^3-a(n-1).
EXAMPLE
a(1)=1; next cube is (a(1)+1)^3=8; "jump over" it: 8+(8-1)=15; a(2)=15; next cube is (a(2)+1)^3=4096; "jump over" it: 4096+(4096-15)=8177.
MAPLE
a(1) := 1; a(n) := 2*(a(n-1)+1)^2-a(n-1);
CROSSREFS
Sequence in context: A205304 A334835 A206295 * A059950 A198979 A249967
KEYWORD
easy,nonn
AUTHOR
Zak Seidov, Sep 26 2002
STATUS
approved

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Last modified May 16 15:32 EDT 2024. Contains 372554 sequences. (Running on oeis4.)