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A073563
Number of Fibonacci numbers F(k), k <= 10^n, whose initial digit is 7.
0
0, 5, 56, 580, 5798, 57992, 579913, 5799197, 57991941, 579919465, 5799194699
OFFSET
1,2
FORMULA
Limit_{n->oo} a(n)/10^n = log(8/7), where the base is 10. - Robert Gerbicz, Sep 05 2002
EXAMPLE
a(2) = 5 because there are 5 Fibonacci numbers up to 10^2 whose initial digit is 7.
PROG
(PARI) lista(nn) = my(m=log(quadgen(5)), c=0, d=log(10)/m, q, r=log(sqrt(5))/m, s=5-log(7)/m, t=5-log(8)/m, u=-3); for(n=1, nn, u=10*u+36; until(u<r+=d, q=frac(r); if(q<s && q>t, c++)); print1(c, ", ")); \\ Jinyuan Wang, Dec 09 2024
CROSSREFS
Sequence in context: A258490 A255953 A174249 * A006658 A221160 A006293
KEYWORD
nonn,base,more
AUTHOR
Shyam Sunder Gupta, Aug 15 2002
EXTENSIONS
More terms from Robert Gerbicz, Sep 05 2002
a(9)-a(11) from Sean A. Irvine and Jinyuan Wang, Dec 10 2024
STATUS
approved