0,4

Table of n, a(n) for n=0..77.

a(n) = ceiling(n*log(10)/(15*log(phi))) +0 or +1.

a(2)=6 because there are 6 Fibonacci numbers F(k) <= 10^2 which end in 0.

(PARI) a(n) = (sum(i=0, ceil(n*log(10)/log((1+sqrt(5))/2)), if(fibonacci(i)%10+1+sign(fibonacci(i)-10^n), 0, 1)))

Different from A002280.

Cf. A008597, A214855.

Sequence in context: A194920 A327440 A285588 * A025786 A085886 A088676

Adjacent sequences: A072909 A072910 A072911 * A072913 A072914 A072915

base,nonn

Shyam Sunder Gupta and Benoit Cloitre, Aug 15 2002

approved