OFFSET
0,5
COMMENTS
This resulted from a question from Richard Ehrenborg and Margie Readdy.
LINKS
Alois P. Heinz, Table of n, a(n) for n = 0..500 (terms n = 1..50 from Vladeta Jovovic)
D. Zeilberger, I Am Sorry, Richard Ehrenborg and Margie Readdy, About Your Two Conjectures, But One Is FAMOUS, While The Other Is FALSE; Local copy [PDF file only, no active links]
FORMULA
G.f.: Sum_{n>=0} a(2n+1)x^(2n+1) = Sum_{i,j >= 0) arctan(x)^(2i+1) (log((1+x^2)/(1-x^2)))^j E(2i+2j+1)/((2i+1)!j!4^j), where E(2i+2j+1) is an Euler number (A000111). There is a similar but more complicated generating function for a(2n). - Richard Stanley, Jan 02 2006
EXAMPLE
a(3)=1 since among the four involutions of length 3 (123, 213, 321, 132), only one is up-down (132).
CROSSREFS
KEYWORD
nonn
AUTHOR
Doron Zeilberger, Jul 01 2002; more terms, Dec 09 2003
EXTENSIONS
More terms from Vladeta Jovovic, May 16 2007
a(0)=1 prepended by Alois P. Heinz, Aug 07 2018
STATUS
approved