OFFSET
1,3
COMMENTS
w = exp(2Pi*I/3) = (-1-Sqrt(-3))/2.
The sequence (2/3)*(1+w^(n+1)+w^(2*n+2)) is "Period 3: repeat [0,2,0]."
LINKS
Index entries for linear recurrences with constant coefficients, signature (3, -1, 1, -3, 1).
FORMULA
G.f.: x^2*(1+x)*(1+x-x^2)/((1-x)*(1-3*x+x^2)*(1+x+x^2)). [Colin Barker, Jan 14 2012]
a(1)=0, a(2)=1, a(3)=5, a(4)=14, a(5)=37, a(n)=3*a(n-1)- a(n-2)+ a(n-3)-3*a(n-4)+a(n-5). - Harvey P. Dale, Aug 19 2012
MATHEMATICA
a[1] = 0; a[2] = 1; w = Exp[2Pi*I/3]; a[n_] := (2/3)(1 + w^n + w^(2n)) + 3a[n - 1] - a[n - 2]; Table[ Simplify[ a[n]], {n, 1, 28}]
LinearRecurrence[{3, -1, 1, -3, 1}, {0, 1, 5, 14, 37}, 30] (* Harvey P. Dale, Aug 19 2012 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Robert G. Wilson v, Jun 24 2002
STATUS
approved