OFFSET
0,2
FORMULA
a(n) = (2*binomial(2*n+1,n)+5*binomial(2*n-2,n+1))/(n+2) for n>0. - Tani Akinari, Jul 24 2025
a(n) ~ 21 * 4^(n-1) / (n^(3/2) * sqrt(Pi)). - Amiram Eldar, Sep 26 2025
MATHEMATICA
a[n_] := (2*Binomial[2*n + 1, n] + 5*Binomial[2*n - 2, n + 1])/(n + 2); a[0] = 1; Array[a, 20, 0] (* Amiram Eldar, Sep 26 2025 *)
PROG
(Maxima) a(n):=if n=0 then 1 else (2*binomial(2*n+1, n)+5*binomial(2*n-2, n+1))/(n+2); makelist(a(n), n, 0, 20); /* Tani Akinari, Jul 24 2025 */
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, Jun 06 2002
STATUS
approved
