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A070985
Number of terms in the simple continued fraction for Sum_{k=1..n} 1/k^2.
2
1, 2, 5, 7, 9, 7, 10, 20, 18, 14, 22, 19, 18, 24, 26, 24, 30, 30, 28, 37, 25, 30, 35, 35, 34, 38, 47, 52, 49, 54, 40, 49, 49, 69, 57, 67, 78, 67, 67, 68, 67, 64, 65, 86, 76, 81, 92, 79, 83, 83, 95, 82, 85, 80, 84, 95, 92, 91, 121, 105, 100, 108, 111, 109, 118, 105, 110, 88
OFFSET
1,2
COMMENTS
Sum_{k>=1} 1/k^2 = zeta(2) = Pi^2/6.
LINKS
FORMULA
Limit_{n ->infinity} a(n)/n = C =1.6....
EXAMPLE
The simple continued fraction for Sum_{k=1..10} 1/k^2 is [1, 1, 1, 4, 1, 1, 10, 4, 1, 2, 5, 2, 1, 24] which contains 14 terms, hence a(10) = 14.
MATHEMATICA
lcf[f_] := Length[ContinuedFraction[f]]; lcf /@ Accumulate[Table[1/k^2, {k, 1, 100}]] (* Amiram Eldar, Apr 30 2022 *)
PROG
(PARI) for(n=1, 100, print1(length(contfrac(sum(i=1, n, 1/i^2))), ", "))
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Benoit Cloitre, May 18 2002
STATUS
approved