login

Year-end appeal: Please make a donation to the OEIS Foundation to support ongoing development and maintenance of the OEIS. We are now in our 61st year, we have over 378,000 sequences, and we’ve reached 11,000 citations (which often say “discovered thanks to the OEIS”).

A070341
a(n) = 3^n mod 11: Repeat (1, 3, 9, 5, 4), period 5.
5
1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9, 5, 4, 1, 3, 9
OFFSET
0,2
COMMENTS
Simple continued fraction expansion of 13/24 + sqrt(8761)/120 = 1.3216684472... - R. J. Mathar, Mar 08 2012
FORMULA
From R. J. Mathar, Apr 13 2010: (Start)
a(n) = a(n-5).
G.f.: (1+3*x+9*x^2+5*x^3+4*x^4)/ ((1-x) * (1+x+x^2+x^3+x^4)). (End)
MATHEMATICA
PowerMod[3, Range[0, 100], 11] (* or *) PadRight[{}, 100, {1, 3, 9, 5, 4}] (* Harvey P. Dale, Feb 05 2012 *)
PROG
(Sage) [power_mod(3, n, 11)for n in range(0, 93)] # Zerinvary Lajos, Nov 24 2009
(PARI) a(n)=lift(Mod(3, 11)^n)
(PARI) a(n)=[1, 3, 9, 5, 4][n%5+1] \\ M. F. Hasler, Mar 04 2011
CROSSREFS
Sequence in context: A358190 A282529 A378903 * A245719 A085851 A373099
KEYWORD
nonn,easy
AUTHOR
N. J. A. Sloane, May 12 2002
STATUS
approved