

A070266


Maximum element in the simple continued fraction expansion of H(n) = 1+1/2+1/3+...+1/n, the nth harmonic number.


4



1, 2, 5, 12, 8, 4, 5, 7, 7, 13, 50, 15, 6, 39, 43, 9, 14, 61, 25, 17, 36, 13, 5, 17, 18, 20, 68, 45, 25, 198, 88, 1090, 120, 244, 29, 29, 24, 111, 567, 22, 20, 37, 1812, 59, 41, 336, 121, 32, 37, 314, 104, 162, 289, 146, 1557, 42, 78, 639, 52, 812, 116, 32, 131, 236, 59
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OFFSET

1,2


LINKS



EXAMPLE

The simple continued fraction expansion of H(10) is [2, 1, 13, 12, 1, 3, 1, 2], hence a(10) = 13.


MATHEMATICA

Table[ Max[ ContinuedFraction[ HarmonicNumber[n]]], {n, 1, 65}]


CROSSREFS



KEYWORD

easy,nonn


AUTHOR



STATUS

approved



