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A068542 Period of the fraction 1/3^n. 3
3, 1, 370, 123456790, 411522633744855967078189300, 137174211248285322359396433470507544581618655692729766803840877914951989026063100 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

The length of the period is the number of digits of a(n): 1, 1, 3, 9, 27, 81, ... The terms a(n) are more precisely the integers made from the digits of a period, starting with the first nonzero digit. - M. F. Hasler, Apr 23 2021

LINKS

Table of n, a(n) for n=1..6.

FORMULA

a(n) = floor(10^(3^max(n-2,0)+L(3^n))/3^n) where L(m) = floor(log10(m)). - M. F. Hasler, Apr 23 2021

EXAMPLE

1/3^3 = 0.0370370370..., hence a(3) = 370.

PROG

(PARI) apply( {A068542(n)=10^(3^max(n-2, 0)+logint(3^n, 10))\3^n}, [1..6]) \\ M. F. Hasler, Apr 23 2021

CROSSREFS

Sequence in context: A049330 A274040 A266363 * A036112 A266230 A134884

Adjacent sequences:  A068539 A068540 A068541 * A068543 A068544 A068545

KEYWORD

nonn

AUTHOR

Benoit Cloitre, Mar 22 2002

STATUS

approved

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Last modified July 1 08:17 EDT 2022. Contains 354953 sequences. (Running on oeis4.)