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A068542
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Period of the fraction 1/3^n.
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3
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OFFSET
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1,1
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COMMENTS
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The length of the period is the number of digits of a(n): 1, 1, 3, 9, 27, 81, ... The terms a(n) are more precisely the integers made from the digits of a period, starting with the first nonzero digit. - M. F. Hasler, Apr 23 2021
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LINKS
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Table of n, a(n) for n=1..6.
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FORMULA
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a(n) = floor(10^(3^max(n-2,0)+L(3^n))/3^n) where L(m) = floor(log10(m)). - M. F. Hasler, Apr 23 2021
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EXAMPLE
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1/3^3 = 0.0370370370..., hence a(3) = 370.
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PROG
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(PARI) apply( {A068542(n)=10^(3^max(n-2, 0)+logint(3^n, 10))\3^n}, [1..6]) \\ M. F. Hasler, Apr 23 2021
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CROSSREFS
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Sequence in context: A049330 A274040 A266363 * A036112 A266230 A134884
Adjacent sequences: A068539 A068540 A068541 * A068543 A068544 A068545
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KEYWORD
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nonn
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AUTHOR
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Benoit Cloitre, Mar 22 2002
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STATUS
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approved
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