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A068097
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a(1) = 1; a(n+1) = smallest triangular numbers starting with a(n).
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0
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OFFSET
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1,2
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LINKS
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FORMULA
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a(n+1) = floor((sqrt(8*10^floor(log(a(n))/log(10))*a(n)+1)+1)/2)*(floor((sqrt(8*10^floor(log(a(n))/log(10))*a(n)+1)+1)/2)+1)/2. - Benoit Cloitre, Feb 25 2002
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PROG
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(PARI) /* with 1000 significant digits : */ a(1)=1, a(2)=10 and for n>2 s=10; for(i=1, 10, s=floor((sqrt(8*10^floor(log(s)/log(10))*s+1)+1)/2)*(floor((sqrt(8*10^floor(log(s)/log(10))*s+1)+1)/2)+1)/2; print1(s, ", "); );
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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