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A067390
Number of distinct prime factors in 2^n + 3.
1
1, 1, 1, 1, 2, 1, 1, 2, 2, 2, 2, 1, 3, 2, 1, 1, 3, 1, 3, 3, 3, 3, 3, 2, 2, 2, 2, 1, 4, 1, 3, 2, 4, 3, 2, 3, 3, 2, 2, 2, 3, 2, 4, 4, 2, 2, 3, 2, 3, 3, 4, 2, 5, 2, 1, 3, 3, 3, 4, 3, 2, 2, 4, 2, 5, 2, 1, 5, 3, 3, 3, 3, 3, 4, 4, 2, 4, 3, 4, 5, 4, 4, 5, 1, 4, 4, 2, 3, 5, 4, 4, 4, 4, 5, 4, 4, 6, 3, 2, 2
OFFSET
1,5
LINKS
FORMULA
a(n) = A001221(A062709(n)). - Amiram Eldar, Feb 06 2020
EXAMPLE
a(5) = 2 since 2^5 + 3 = 35 = 5 * 7 has 2 distinct prime factors.
MATHEMATICA
PrimeNu @ Table[2^n + 3, {n, 1, 50}] (* Amiram Eldar, Feb 06 2020 *)
PROG
(Magma) [#PrimeDivisors(2^n+3):n in [1..100]]; // Marius A. Burtea, Feb 06 2020
CROSSREFS
Sequence in context: A182599 A183015 A183018 * A256945 A282091 A354110
KEYWORD
nonn
AUTHOR
Benoit Cloitre, Feb 23 2002
STATUS
approved