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A065554
Numbers k such that floor((3/2)^(k+1))/floor((3/2)^k) = 3/2.
10
2, 9, 11, 13, 24, 29, 31, 36, 37, 40, 41, 43, 49, 50, 51, 67, 68, 70, 72, 73, 77, 79, 80, 86, 88, 91, 92, 95, 101, 102, 103, 115, 121, 126, 127, 132, 134, 136, 142, 145, 146, 151, 154, 156, 162, 165, 167, 171, 172, 176, 178, 179, 181, 191, 193, 194, 195, 198, 199
OFFSET
1,1
COMMENTS
Also k such that A002380(k+1) = 3*A002380(k). - Benoit Cloitre, Apr 21 2003
It appears that lim_{n->oo} a(n)/n = 3. - Benoit Cloitre, Jan 29 2006
LINKS
MATHEMATICA
a[1] = 2; a[n_ ] := a[n] = Block[ {k = a[n - 1] + 1}, While[ Floor[(3/2)^(k + 1)] / Floor[(3/2)^k] != 3/2, k++ ]; Return[k]]; Table[ a[n], {n, 1, 70} ]
PROG
(PARI) isok(k) = { my(f=3/2); floor(f^(k+1))/floor(f^k) == f } \\ Harry J. Smith, Oct 22 2009
CROSSREFS
Sequence in context: A072065 A137000 A073634 * A034042 A138759 A345925
KEYWORD
nonn,changed
AUTHOR
Benoit Cloitre, Nov 28 2001
EXTENSIONS
More terms from Robert G. Wilson v, Nov 30 2001
STATUS
approved