|
|
A065158
|
|
Table of reduced binary string substitutions: a(i,j) is obtained by substituting i for each 1-bit in j, then dividing by i.
|
|
3
|
|
|
1, 1, 2, 1, 2, 3, 1, 2, 5, 4, 1, 2, 5, 4, 5, 1, 2, 9, 4, 9, 6, 1, 2, 9, 4, 9, 10, 7, 1, 2, 9, 4, 17, 10, 21, 8, 1, 2, 9, 4, 17, 18, 21, 8, 9, 1, 2, 17, 4, 17, 18, 73, 8, 17, 10, 1, 2, 17, 4, 17, 18, 73, 8, 17, 18, 11, 1, 2, 17, 4, 33, 18, 73, 8, 33, 18, 37, 12, 1, 2, 17, 4, 33, 34, 73, 8, 33
(list;
table;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,3
|
|
COMMENTS
|
Table origin is a(1,1). a(1,n)=n. a(n,1)=1. By convention a(0,n)=a(n,0)=0. a(i,j)=A065157(i,j)/i. a(n,n)=A065160(n)=A065159(n)/n.
|
|
LINKS
|
|
|
EXAMPLE
|
a(3,5): 5=101->(3)0(3)=(11)0(11)=11011=27; 27/3=9. a(5,3): 3=11->(5)(5)=(101)(101)=101101=45; 45/5=9
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|