|
|
A065098
|
|
Sum of reciprocals of terms in period of continued fraction for sqrt(n) is an integer.
|
|
0
|
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
No additional terms up to n = 1 million. - Harvey P. Dale, Apr 11 2016
|
|
LINKS
|
|
|
EXAMPLE
|
For n=239 the quotient periods are: [[15],[2,5,1,2,4,15,4,2,1,5,2,30]], (1/2)+(1/5)+1+(1/2)+(1/4)+(1/15)+(1/4)+(1/2)+1+(1/5)+(1/2)+(1/30) = 5.
|
|
MATHEMATICA
|
Do[ If[ IntegerQ[ Apply[ Plus, 1/Last[ ContinuedFraction[ Sqrt[n]]]]], Print[n]], {n, 2, 10^5 } ]
srcfiQ[n_]:=Module[{s=Sqrt[n]}, IntegerQ[If[IntegerQ[s], 1/2, Total[1/ ContinuedFraction[s][[2]]]]]]; Select[Range[25000], srcfiQ] (* Harvey P. Dale, Apr 11 2016 *)
|
|
CROSSREFS
|
|
|
KEYWORD
|
nonn,bref
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|