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A064107 Continued fraction quotients for e^e = 15.15426223. 6
15, 6, 2, 13, 1, 3, 6, 2, 1, 1, 5, 1, 1, 1, 9, 4, 1, 1, 1, 6, 7, 1, 2, 4, 1, 2, 2, 24, 1, 2, 4, 56, 1, 1, 2, 4, 1, 75, 1, 5, 1, 2, 2, 1, 137, 2, 2, 97, 3, 16, 1, 1, 1, 1, 3, 5, 12, 1, 1, 2, 1, 53, 1, 2, 5, 3, 2, 4, 1, 2, 1, 39, 1, 2, 1, 4, 1, 11, 1, 5, 5, 1, 4, 1, 17, 12, 4, 82, 1, 4, 6, 25, 3, 2, 3 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

It was conjectured (but remains unproved) that this sequence is infinite and aperiodic, but it is difficult to find who first posed this problem. [Vladimir Reshetnikov, Apr 27 2013]

LINKS

Harry J. Smith, Table of n, a(n) for n=1,...,20000

Eric Weisstein's World of Mathematics, Transcendental Number

Wikipedia, List of unsolved problems in mathematics, Analysis

Wikipedia, Irrational number, Open_questions

EXAMPLE

15.154262241479264189760430... = 15 + 1/(6 + 1/(2 + 1/(13 + 1/(1 + ...)))). [Harry J. Smith, Apr 30 2009]

MAPLE

with(numtheory): cfrac(evalf((exp(1))^(exp(1)), 2560), 256, 'quotients');

MATHEMATICA

ContinuedFraction[E^E, 100] (* Harvey P. Dale, Sep 29 2012 *)

PROG

(PARI) { allocatemem(932245000); default(realprecision, 21000); x=contfrac(exp(exp(1))); for (n=1, 20000, write("b064107.txt", n, " ", x[n])); } [Harry J. Smith, Apr 30 2009]

CROSSREFS

Cf. A058287, A058288, A159825.

Sequence in context: A249996 A128251 A292307 * A116907 A277384 A040214

Adjacent sequences:  A064104 A064105 A064106 * A064108 A064109 A064110

KEYWORD

cofr,nonn

AUTHOR

Labos Elemer, Sep 17 2001

STATUS

approved

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Last modified June 18 14:52 EDT 2019. Contains 324213 sequences. (Running on oeis4.)