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A060224
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Number of orbits of length n under the map whose periodic points are counted by A047863.
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0
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2, 2, 8, 39, 288, 3046, 47232, 1061100, 34385064, 1601137110, 106806380544, 10186152828755, 1386394018652160, 268976332493883474, 74301040560350828856, 29201332000320392849280, 16315436194909017151242240, 12952804290011844088808158188, 14603450579455204338154338779136
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OFFSET
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1,1
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LINKS
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FORMULA
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a(n) = (1/n)* Sum_{ d divides n } mu(d)*A047863(n/d).
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EXAMPLE
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a(5)=288 since the 6th term of A047863 is 1442 and the 2nd term is 2, so there must be (1442-2)/5 = 288 orbits of length 5.
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PROG
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(PARI) a047863(n) = n!*polcoeff(sum(k=0, n, exp(2^k*x +x*O(x^n))*x^k/k!), n);
a(n) = (1/n)*sumdiv(n, d, moebius(d)*a047863(n/d)); \\ Michel Marcus, Sep 11 2017
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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