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A059652
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a(n) = [[(k^2)*n]-(k*[k*n])], where k = sqrt(3/2) and [] is the floor function.
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2
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0, -1, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, -1, 0, 0, 1, -1, 0, 0, 1, -1, 0, 0, 0, 0, 0, 0, 0, 0, 0, -1, 0, 0, 1, -1, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, -1, 0, 0, 1, -1, 0, 0, 1, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, -1, 0, 0, 1, -1, 0, 0, 1, -1, 0, 0, 0, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, -1, 0, 0, 1, -1, 0, 0, 1, -1, 0, 0, 0, 0, 0, -1, 0, 0, 0, -1, 0, 0
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OFFSET
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0,1
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COMMENTS
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The values of (floor((k^2)*j)-(k*(floor(k*j)))) for j=0..45, with k=2^(1/3), are 0, -0.224746, 0.550508, 0.325762, 1.101016, -0.348476, 0.426778, 0.202032, 0.97729, ...
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LINKS
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MAPLE
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Digits := 89; floor_diffs_floored(sqrt(3/2), 120);
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CROSSREFS
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A059648 gives similar sequence for k=sqrt(2). Positions of ones: A059653, positions of minus ones: A059655.
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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