OFFSET
0,2
COMMENTS
From Enrique Navarrete, Nov 08 2025: (Start)
Convolution of the powers of 4 with the triangular numbers [1, 3, 6, 10, ...].
Equivalently, third partial sums of A000302. (End)
REFERENCES
A. H. Beiler, Recreations in the Theory of Numbers, Dover, N.Y., 1964, pp. 194-196.
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (7,-15,13,-4).
FORMULA
a(n) = (2^(2*n+7) - (9*n^2 + 51*n + 74))/54.
a(n) = 4*a(n-1) + C(n+2,2); a(0)=1.
a(n) = Sum_{k=0..n} binomial(n+3, k+3)*3^k. - Paul Barry, Aug 20 2004
G.f.: 1/((1-x)^3*(1-4*x)). - Colin Barker, Jan 12 2012
a(n) = 7*a(n-1) - 15*a(n-2) + 13*a(n-3) - 4*a(n-4), n >= 4. - Enrique Navarrete, Nov 02 2025
E.g.f.: exp(x)*(128*exp(3*x) - 9*x^2 - 60*x - 74)/54. - Enrique Navarrete, Nov 04 2025
MATHEMATICA
CoefficientList[Series[1/((1-x)^3*(1-4*x)), {x, 0, 25}], x] (* Vincenzo Librandi, Apr 28 2012 *)
PROG
(Magma) [((2^(2*n+7))-(9*(n^2)+51*n+74))/54: n in [0..25]]; // Vincenzo Librandi, Apr 28 2012
CROSSREFS
KEYWORD
easy,nonn
AUTHOR
Barry E. Williams, Jan 25 2000
STATUS
approved
