A051068 Partial sums of A014578.

0, 1, 2, 2, 3, 4, 4, 5, 6, 7, 8, 9, 9, 10, 11, 11, 12, 13, 14, 15, 16, 16, 17, 18, 18, 19, 20, 20, 21, 22, 22, 23, 24, 24, 25, 26, 27, 28, 29, 29, 30, 31, 31, 32, 33, 34, 35, 36, 36, 37, 38, 38, 39, 40, 40, 41, 42, 42, 43, 44, 44, 45, 46, 47, 48, 49, 49

Offset

0,3

Comments

Duplicate of A050294? [Joerg Arndt, Apr 27 2013]

From Michel Dekking, Feb 10 2019: (Start)

The answer to Joerg Arndt's question is: yes (modulo an offset). To see this, it suffices to prove that the two sequences of first differences Da and Db of a= A051068 and b:=A050294 are equal. Clearly the sequence Da of first differences of a is the sequence A014578. According to Philippe Deleham (2004), Da equals 0x = 0110110111110..., where x is the fixed point of the morphism 0->111, 1->110.

From Vladimir Shevelev (2011) we know a formula for b=A050294: b(n) = n-b(floor(n/3)). This gives that the sequence of first differences Db:=(b(n+1)-b(n)) of b satisfies

Db(3m+1) = Db(3m+2) = 1, and Db(3m+3) = 1 - Db(m).

This implies that Db = x, the fixed point of 0->111, 1->110.

(End)

Links

Table of n, a(n) for n=0..66.

Formula

a(3^n) = A015518(n+1) = -(-1)^n*A014983(n+1). - Philippe Deléham, Mar 31 2004

Crossrefs

Cf. A014578, A051069, A050294.

Sequence in context: A127038 A175268 A241948 * A050294 A349775 A369870

Adjacent sequences: A051065 A051066 A051067 * A051069 A051070 A051071

Keyword

nonn

Author

N. J. A. Sloane, Gary W. Adamson

Status

approved