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A047929 a(n) = n^2*(n-1)*(n-2). 5
0, 18, 96, 300, 720, 1470, 2688, 4536, 7200, 10890, 15840, 22308, 30576, 40950, 53760, 69360, 88128, 110466, 136800, 167580, 203280, 244398, 291456, 345000, 405600, 473850, 550368, 635796, 730800, 836070, 952320, 1080288, 1220736 (list; graph; refs; listen; history; text; internal format)
OFFSET
2,2
COMMENTS
There are 5 ways to put parentheses in the expression a - b - c - d: (a - (b - c)) - d, ((a - b) - c) - d, (a - b) - (c - d), a - (b - (c - d)), a - ((b - c) - d). This sequence describes how many sets of natural numbers [a,b,c,d] can be produced with the numbers {0,1,2,3,...,n} such that all the distinct expressions take different values. A045991 describes the similar process for a - b - c. For example, no sets can be produced with only 0's or only 0's and 1's; with {0,1,2,3}, 18 such sets can be produced. - Asher Auel, Jan 26 2000
For n >= 3, a(n)/6 is the number of permutations of n symbols that 3-commute with an n-cycle (see A233440 for definition). - Luis Manuel Rivera Martínez, Feb 24 2014
LINKS
Luis Manuel Rivera, Integer sequences and k-commuting permutations, arXiv preprint arXiv:1406.3081 [math.CO], 2014-2015.
FORMULA
a(n) = A004320(n-2)*6.
G.f.: 6*x^3*(3 + x)/(1 - x)^5. - Stefano Spezia, May 20 2021
a(n) = 5*a(n-1) - 10*a(n-2) + 10*a(n-3) - 5*a(n-4) + a(n-5). - Wesley Ivan Hurt, May 22 2021
From Amiram Eldar, May 25 2021: (Start)
Sum_{n>=3} 1/a(n) = (Pi^2 - 9)/12.
Sum_{n>=3} (-1)^(n+1)/a(n) = Pi^2/24 + 2*log(2) - 7/4. (End)
MATHEMATICA
Drop[CoefficientList[Series[6 x^3*(3 + x)/(1 - x)^5, {x, 0, 34}], x], 2] (* Michael De Vlieger, May 21 2021 *)
PROG
(Magma) [n^2*(n-1)*(n-2): n in [2..40]]; // Vincenzo Librandi, May 02 2011
(PARI) a(n)=n^4 - 3*n^3 + 2*n^2 \\ Charles R Greathouse IV, May 02, 2011
CROSSREFS
Sequence in context: A186122 A275253 A034725 * A243995 A264202 A338783
KEYWORD
nonn,easy
AUTHOR
STATUS
approved

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Last modified December 6 01:58 EST 2023. Contains 367594 sequences. (Running on oeis4.)