OFFSET
0,4
LINKS
Seiichi Manyama, Table of n, a(n) for n = 0..1000
FORMULA
It appears that for n>11, a(n) = floor((n^2+3n-6)/4). - Ralf Stephan, Jun 10 2005
PROG
(PARI) a(n) = #Set(Vec(prod(k=1, n, 1+x^k))); \\ Seiichi Manyama, Feb 01 2024
(Python)
from collections import Counter
def A039822(n):
c = {0:1}
for k in range(1, n+1):
d = Counter(c)
for j in c:
d[j+k] += c[j]
c = d
return len(set(c.values()))+int(max(c)+1>len(c)) # Chai Wah Wu, Feb 04 2024
CROSSREFS
KEYWORD
nonn
AUTHOR
EXTENSIONS
a(0)=1 prepended by Seiichi Manyama, Feb 01 2024
STATUS
approved