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 A038522 On a (2n+1) X (2n+1) board, let m(i) be the number of squares that are i knight's moves from center; sequence gives max m(i) for i >= 0. 2
 1, 1, 8, 20, 32, 52, 68, 76, 96, 96, 120, 120, 148, 148, 176, 176, 204, 204, 232, 232, 260, 260, 288, 288, 316, 316, 344, 344, 372, 372, 400, 400, 428, 428, 456, 456, 484, 484, 512, 512, 540, 540, 568, 568, 596, 596, 624, 624, 652, 652, 680, 680, 708, 708 (list; graph; refs; listen; history; text; internal format)
 OFFSET 0,3 LINKS Colin Barker, Table of n, a(n) for n = 0..1000 Andreas P. Hadjipolakis, Problem E2605, Am. Math. Monthly Vol. 83 (1976), no. 7 (Aug-Sept.), p. 566. Roger Weitzenkamp, Solution to Problem E2605: Labels on a Chessboard, Am. Math. Monthly Vol. 84 (1977), p. 822. Index entries for linear recurrences with constant coefficients, signature (1,1,-1). FORMULA a(n) = 28*floor(n/2) - 20 for n >= 10. - Andrew Howroyd, Feb 28 2020 From Stefano Spezia, Feb 29 2020: (Start) G.f.: (1 + 6*x^2 + 12*x^3 + 5*x^4 + 8*x^5 + 4*x^6 - 12*x^7 + 4*x^8 - 8*x^9 + 4*x^10 + 4*x^12)/((1 - x)^2*(1 + x)). a(n) = a(n-1) + a(n-2) - a(n-3) for n > 12. (End) EXAMPLE On a 5 X 5 board, [ m(0),...,m(4) ]=[ 1,8,8,4,4 ], max=8, so a(2)=8. MATHEMATICA LinearRecurrence[{1, 1, -1}, {1, 1, 8, 20, 32, 52, 68, 76, 96, 96, 120, 120, 148}, 60] (* Harvey P. Dale, Apr 15 2020 *) PROG (PARI) Vec((1 + x^2)*(1 + 5*x^2 + 12*x^3 - 4*x^5 + 4*x^6 - 8*x^7 + 4*x^10) / ((1 - x)^2*(1 + x)) + O(x^50)) \\ Colin Barker, Mar 16 2020 CROSSREFS Cf. A018842. Sequence in context: A339273 A017617 A246309 * A267435 A186293 A158865 Adjacent sequences:  A038519 A038520 A038521 * A038523 A038524 A038525 KEYWORD easy,nonn,walk,nice AUTHOR Antreas P. Hatzipolakis (xpolakis(AT)hol.gr) EXTENSIONS Corrected and additional terms added by Andrew Howroyd, Feb 28 2020 STATUS approved

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Last modified May 13 14:47 EDT 2021. Contains 343860 sequences. (Running on oeis4.)