OFFSET
0,3
FORMULA
From Amiram Eldar, Sep 04 2025: (Start)
a(n) = binomial(2*n+4, n+5)*(n^2+5*n+1)/(n+6);
a(n) ~ 2^(2*n+4) * sqrt(n/Pi). (End)
MATHEMATICA
a[n_] := Binomial[2*n + 4, n + 5]*(n^2 + 5*n + 1)/(n + 6); Array[a, 25, 0] (* Amiram Eldar, Sep 04 2025 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
EXTENSIONS
Corrected and extended by N. J. A. Sloane, Apr 21 2000
STATUS
approved
