OFFSET
0,5
COMMENTS
A000105(n) + a(n) = A000988(n) because the number of free polyominoes plus the number of polyominoes lacking bilateral symmetry equals the number of one-sided polyominoes. - Graeme McRae, Jan 05 2006
Each chiral pair is counted as one. - Robert A. Russell, Feb 23 2022
LINKS
Robert A. Russell, Table of n, a(n) for n = 0..59 (terms 23..45 from Andrew Howroyd, 46..48 from Robert A. Russell, 49..50 from John Mason, 51..59 from Toshihiro Shirakawa)
D. H. Redelmeier, Counting polyominoes: yet another attack, Discrete Math., 36 (1981), 191-203.
Toshihiro Shirakawa, Enumeration of Polyominoes up to Size N=59, arXiv:2510.22446 [math.CO], 2025.
FORMULA
EXAMPLE
For a(4)=2, the two chiral pairs of tetrominoes are XXX XXX and XX XX.
X X XX XX
MATHEMATICA
Array[a, 60] (* Jean-François Alcover, Sep 08 2019, after Graeme McRae *)
CROSSREFS
KEYWORD
nonn
AUTHOR
EXTENSIONS
Terms a(23) and beyond from Andrew Howroyd, Dec 04 2018
Name edited by Robert A. Russell, Feb 03 2019
a(0)=0 corrected by John Mason, Jan 12 2023
STATUS
approved
