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A027433 Sum over all 2^(2n) pairs (u,v) of binary sequences of length n of length of maximal common subsequence between them. 2
0, 2, 18, 116, 646, 3324, 16302, 77356, 358424, 1630988, 7317424, 32458400, 142638568, 621948448, 2693978986, 11602817444, 49726594628, 212195409348, 902038055526, 3821542566420, 16141064174876, 67988725603820, 285670814425030, 1197613640781032, 5010423893820844 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,2
COMMENTS
The proved bounds for gamma_2 (see asymptotic formula below) are 0.788071 <= gamma_2 <= 0.82628, and conjectured value is around 0.811 [see Dixon].
LINKS
Vacláv Chvátal and David Sankoff, Longest Common Subsequences of Two Random Sequences, Journal of Applied Probability, Vol. 12, No. 2 (Jun., 1975), pp. 306-315, DOI: 10.2307/3212444.
V. Dancik and M. Paterson, Upper bounds for the expected length of a longest common subsequence of two binary sequences, in STACS 94, Proceedings of the Eleventh Annual Symposium on Theoretical Aspects of Computer Science held in Caen, Feb 24 1994. Edited by P. Enjalbert, E. W. Mayr and K. W. Wagner. Lecture Notes in Computer Science, 775. Springer-Verlag, 1994, pp. 669-678.
J. D. Dixon, Longest common subsequences in binary sequences, arXiv preprint arXiv:1307.2796 [math.GR], 2013.
FORMULA
a(n) ~ gamma_2*n*4^n, where gamma_2 is the Chvátal-Sankoff constant.
MATHEMATICA
a[0] = 0;
a[n_] := a[n] = With[{s = Partition[Tuples[{0, 1}, n], 2^(n-1)], f = Composition[Length, LongestCommonSequence]}, 2^n n + 4 Total[ReleaseHold[LowerTriangularize[Outer[Hold[f], s[[1]], s[[1]], 1], -1]], 2] + 2 Total[Outer[f, s[[1]], s[[2]], 1], 2]];
Table[a[n], {n, 0, 10}] (* Vladimir Reshetnikov, May 12 2016 *)
CROSSREFS
Sequence in context: A308700 A064837 A224902 * A153338 A007798 A058052
KEYWORD
nonn,hard
AUTHOR
EXTENSIONS
More terms from Alexander D. Healy, Dec 17 2002
a(19)-a(24) from Yi Yang, Nov 04 2013
a(25)-a(28) from Yi Yang, May 10 2022
STATUS
approved

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Last modified August 10 08:32 EDT 2024. Contains 375044 sequences. (Running on oeis4.)