OFFSET
1,2
COMMENTS
Or, starting from the natural number, delete successively from the working sequence the term in position 2*a(n). From natural numbers, delete the term in position 2*1, i.e., 2. This leaves 1,3,4,5,6,7,8,9,10,11,... . Delete now the term in position 2*3=6, i.e., 7. This leaves 1,3,4,5,6,8,9,10,11,... . Delete now the term in position 2*4=8, i.e., 10. This leaves 1,3,4,5,6,8,9,11,... and so on. - Philippe Lallouet (philip.lallouet(AT)wanadoo.fr), Aug 20 2007
The term deleted from the n-th working sequence is equal to A026364(n), which means that all integers which are not in the present sequence are in A026364 and no others. - Philippe Lallouet (philip.lallouet(AT)orange.fr), May 05 2008
Complement of A026364; also the rank transform (as at A187224) of A004526 after removal of its first three terms, leaving (1,2,2,3,3,4,4,5,5,6,6,...). - Clark Kimberling, Mar 10 2011
Positions of 1 in the fixed point of the morphism 0->11, 1->101; see A285430.
Conjecture: -1 < n*r - a(n) < 2 for n>=1, where r = (1 + sqrt(3))/2. - Clark Kimberling, Apr 29 2017
LINKS
Carmine Suriano, Table of n, a(n) for n = 1..10000
FORMULA
a(1)=1, then a(n)=a(n-1)+2 if n is even and n/2 is not in the sequence, a(n)=a(n-1)+1 otherwise (in particular a(2k+1)=a(2k)+1). a(n)=(1+sqrt(3))/2*n+O(1). Taking a(0)=0, for n>=1 a(2n)-a(2n-2)=A080428(n). - Benoit Cloitre, Apr 23 2008
MATHEMATICA
seqA = Table[Floor[(n+2)/2], {n, 1, 180}] (* A004526 *)
seqB = Table[n, {n, 1, 80}]; (* A000027 *)
jointRank[{seqA_, seqB_}] := {Flatten@Position[#1, {_, 1}],
Flatten@Position[#1, {_, 2}]} &[Sort@Flatten[{{#1, 1} & /@ seqA, {#1, 2} & /@ seqB}, 1]];
limseqU = FixedPoint[jointRank[{seqA, #1[[1]]}] &, jointRank[{seqA, seqB}]][[1]] (* A026363 *)
Complement[Range[Length[seqA]], limseqU] (* A026364 *)
(* Peter J. C. Moses, Mar 10 2011 *)
s = Nest[Flatten[# /. {0 -> {1, 1}, 1 -> {1, 0, 1}}] &, {0}, 13] (* A285430 *)
Flatten[Position[s, 0]] (* A026364 *)
Flatten[Position[s, 1]] (* A026363 *)
(* Clark Kimberling, Apr 28 2017 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
STATUS
approved