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A024841 a(n) = least m such that if r and s in {1/1, 1/3, 1/5, ..., 1/(2n-1)} satisfy r < s, then r < k/m < (k+2)/m < s for some integer k. 3
5, 19, 41, 71, 109, 155, 222, 287, 376, 460, 571, 673, 806, 926, 1081, 1219, 1396, 1552, 1751, 1926, 2147, 2380, 2584, 2839, 3106, 3338, 3627, 3928, 4188, 4511, 4846, 5134, 5491, 5860, 6176, 6567, 6970, 7385, 7740, 8177, 8626, 9087, 9481, 9964, 10459, 10966, 11398 (list; graph; refs; listen; history; text; internal format)
OFFSET

2,1

COMMENTS

For a guide to related sequences, see A001000. - Clark Kimberling, Aug 12 2012

LINKS

Clark Kimberling, Table of n, a(n) for n = 2..100

MATHEMATICA

leastSeparatorS[seq_, s_] := Module[{n = 1},

Table[While[Or @@ (Ceiling[n #1[[1]]] <

s + 1 + Floor[n #1[[2]]] &) /@ (Sort[#1, Greater] &) /@

Partition[Take[seq, k], 2, 1], n++]; n, {k, 2, Length[seq]}]];

t = Map[leastSeparatorS[1/(2*Range[50]-1), #] &, Range[5]];

t[[3]] (* A024841 *)

(* Peter J. C. Moses, Aug 06 2012 *)

CROSSREFS

Cf. A001000, A024842.

Sequence in context: A262997 A031379 A125202 * A155737 A100572 A119534

Adjacent sequences: A024838 A024839 A024840 * A024842 A024843 A024844

KEYWORD

nonn

AUTHOR

Clark Kimberling

STATUS

approved

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Last modified March 25 04:11 EDT 2023. Contains 361511 sequences. (Running on oeis4.)