A022911 Arrange the nontrivial binomial coefficients C(m,k) (2 <= k <= m/2) in increasing order (not removing duplicates); record the sequence of m's.

4, 5, 6, 6, 7, 8, 7, 9, 10, 11, 8, 12, 8, 13, 9, 14, 15, 16, 10, 9, 17, 18, 11, 19, 20, 21, 10, 12, 22, 10, 23, 24, 13, 25, 26, 11, 27, 14, 28, 29, 30, 15, 11, 31, 12, 32, 33, 16, 34, 35, 36, 37, 17, 38, 13, 39, 40, 12, 18, 41, 42, 43, 12, 44, 19, 45, 14, 46, 47, 48

Offset

1,1

Comments

In case of duplicates, the m values are listed in decreasing order. Thus a(18)=16 and a(19)=10 corresponding to binomial(16,2)=binomial(10,3)=120. - Robert Israel, Sep 18 2018

Links

Robert Israel, Table of n, a(n) for n = 1..10000

Sean A. Irvine, Java program (github)

Formula

A319382(n) = binomial(a(n),A022912(n)). - Robert Israel, Sep 18 2018

Maple

N:= 10000: # for binomial(n, k) values <= N
Res:= NULL:
for n from 2 while n*(n-1)/2 <= N do
  for k from 2 to n/2 do
    v:= binomial(n, k);
    if v > N then break fi;
    Res:= Res, [v, n, k]
od od:
Res:= sort([Res], proc(p, q) if p[1]<>q[1] then  p[1]<q[1]
  elif p[2]<>q[2] then p[2]>q[2]
  fi end proc):
map(t -> t[2], Res); # Robert Israel, Sep 18 2018

Crossrefs

Cf. A003015, A006987, A022912, A319382.

Sequence in context: A046343 A273227 A319500 * A162310 A116962 A273777

Adjacent sequences: A022908 A022909 A022910 * A022912 A022913 A022914

Keyword

nonn

Author

Clark Kimberling

Status

approved