A010977 a(n) = binomial coefficient C(n,24).

1, 25, 325, 2925, 20475, 118755, 593775, 2629575, 10518300, 38567100, 131128140, 417225900, 1251677700, 3562467300, 9669554100, 25140840660, 62852101650, 151584480450, 353697121050, 800472431850, 1761039350070, 3773655750150, 7890371113950, 16123801841550

Offset

24,2

Links

T. D. Noe, Table of n, a(n) for n = 24..1000

Index entries for linear recurrences with constant coefficients, signature (25, -300, 2300, -12650, 53130, -177100, 480700, -1081575, 2042975, -3268760, 4457400, -5200300, 5200300, -4457400, 3268760, -2042975, 1081575, -480700, 177100, -53130, 12650, -2300, 300, -25, 1).

Formula

G.f.: x^24/(1-x)^25. - Zerinvary Lajos, Aug 04 2008 [Corrected by Georg Fischer, May 19 2019]

a(n) = n/(n-24) * a(n-1), n > 24. - Vincenzo Librandi, Mar 26 2011

From Amiram Eldar, Dec 11 2020: (Start)

Sum_{n>=24} 1/a(n) = 24/23.

Sum_{n>=24} (-1)^n/a(n) = A001787(24)*log(2) - A242091(24)/23! = 201326592*log(2) - 15566188845789952/111546435 = 0.9627768409... (End)

Maple

seq(binomial(n, 24), n=24..41); # Zerinvary Lajos, Aug 04 2008

Mathematica

Table[Binomial[n, 24], {n, 24, 50}] (* Vladimir Joseph Stephan Orlovsky, Apr 26 2011 *)

Prog

(Magma) [ Binomial(n, 24): n in [24..90]]; // Vincenzo Librandi, Mar 26 2011
(PARI) x='x+O('x^50); Vec(x^24/(1-x)^25) \\ G. C. Greubel, Nov 23 2017

Crossrefs

Pascal's triangle A007318 diagonal. - Zerinvary Lajos, Aug 04 2008

Cf. A010970, A010971, A010972, A001787, A242091.

Sequence in context: A243089 A079875 A162702 * A022589 A344656 A199657

Adjacent sequences: A010974 A010975 A010976 * A010978 A010979 A010980

Keyword

nonn

Author

N. J. A. Sloane

Status

approved