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A008498
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4-dimensional centered tetrahedral numbers.
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3
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1, 6, 21, 56, 126, 251, 456, 771, 1231, 1876, 2751, 3906, 5396, 7281, 9626, 12501, 15981, 20146, 25081, 30876, 37626, 45431, 54396, 64631, 76251, 89376, 104131, 120646, 139056, 159501, 182126
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OFFSET
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0,2
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COMMENTS
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Binomial transform of (1,5,10,10,5,0,0,0,...). - Paul Barry, Jul 01 2003
If X is an n-set and Y a fixed 5-subset of X then a(n-5) is equal to the number of 5-subsets of X intersecting Y. - Milan Janjic, Jul 30 2007
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REFERENCES
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E. Deza and M. M. Deza, Figurate numbers, World Scientific Publishing (2012), page 224 (general formula for n-th centered polytope number).
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LINKS
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FORMULA
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G.f.: (1-x^5)/(1-x)^6 = (1 +x +x^2 +x^3 +x^4)/(1-x)^5.
a(n) = C(n,0) + 5*C(n,1) + 10*C(n,2) + 10*C(n,3) + 5*C(n,4). - Paul Barry, Jul 01 2003
a(n) = (5*n^4 + 10*n^3 + 55*n^2 + 50*n + 24)/24. - Paul Barry, Jul 01 2003
E.g.f.: (24 + 120*x + 120*x^2 + 40*x^3 + 5*x^4)*exp(x)/24. - G. C. Greubel, Nov 08 2019
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MAPLE
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[seq(binomial(n+5, 5)-binomial(n, 5), n=0..45)]; # Zerinvary Lajos, Jul 21 2006
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MATHEMATICA
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LinearRecurrence[{5, -10, 10, -5, 1}, {1, 6, 21, 56, 126}, 40] (* Harvey P. Dale, Dec 18 2013 *)
Table[1 + 5n(n+1)(n^2 +n +10)/24, {n, 0, 40}] (* Bruno Berselli, Jun 18 2015 *)
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PROG
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(Magma) [(5*n^4+10*n^3+55*n^2+50*n+24)/24: n in [0..30] ]; // Vincenzo Librandi, Aug 21 2011
(Magma) [Binomial(n+5, 5) - Binomial(n, 5): n in [0..40]]; // G. C. Greubel, Nov 08 2019
(Sage) [binomial(n+5, 5) - binomial(n, 5) for n in (0..40)] # G. C. Greubel, Nov 08 2019
(GAP) List([0..40], n-> Binomial(n+5, 5) - Binomial(n, 5)); # G. C. Greubel, Nov 08 2019
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CROSSREFS
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KEYWORD
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nonn,easy
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AUTHOR
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STATUS
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approved
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